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Search Resources (11 Results)
  Resource NameRatingViews
Solutions | Approved: 6 years ago | 53.2 kB | Comments: 0
Category: Chemistry | Downloaded: 0
N/A 329
Lecture Notes | Approved: 7 years ago | 42 kB | Comments: 0
Category: Computer Science | Downloaded: 0
N/A 146
Lecture Notes | Approved: 7 years ago | 312.55 kB | Comments: 0
Category: Statistics and Probability | Downloaded: 0
...?? ? ? (i=1,..,p) are the slope...
...SAS CODE: options ps=62 ls=80; data in;...
...CODE: options ps=62 ls=80; data in; input...
...the Y-intercept ?i (i=1,..,p) are the slope...
...SAS CODE options ps=62 ls=80; data in;...
...CODE options ps=62 ls=80; data in; input...
...Probability modeled is PF=1. Model Convergence Status...
...Status Convergence criterion (GCONV=1E-8) satisfied. Model Fit...
...Global Null Hypothesis: BETA=0 Test Chi-Square DF...
N/A 108
Lecture Notes | Approved: 7 years ago | 467 kB | Comments: 0
Category: Chemical Engineering | Downloaded: 0
N/A 148
Lecture Notes | Approved: 7 years ago | 147.15 kB | Comments: 0
Category: Chemical Engineering | Downloaded: 0
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Solutions | Approved: 7 years ago | 656.29 kB | Comments: 0
Category: Physics | Downloaded: 0
...I pendulum is T=2? , the period...
...simultaneously, we find A=1272. atm ?3 and...
...2 P19.16 (a) ??AAT=2? i : ?A=×°...
...Nm m 1110 °C=396 N C° 8...
...flask increases as ??VVTgi=3? . Therefore, the...
...since Aw= , ??AAT=2? . The approximation...
...the volume is: V=F I G JT...
...u2 =3200., MafAr u=3995. and MbgCO u2...
...10 2 2?6 P=1999958. m M ejej20.010...
...2sin? This yields h=454. m, a remarkably...
...value compared to ?L=550. cm. *P19.74 (a)...
N/A 220
Lecture Notes | Approved: 7 years ago | 91.18 kB | Comments: 0
Category: Calculus | Downloaded: 0
N/A 221
Lecture Notes | Approved: 7 years ago | 173.02 kB | Comments: 0
Category: Calculus | Downloaded: 0
...f (xi*)?x n??? i=1 Example: Let’s finish...
...= x between x=0and x=1. Using right...
...x between x=0and x=1. Using right endpoints,...
...=sin x ? x=and x= . Using...
...2+ x between x=1 and x=4. Using...
...between x=1 and x=4. Using right endpoints,...
...*)?x n??? i i=1 Definition: If f...
...* * * x=axx… xn=b be the...
...* * x=axx… xn=b be the endpoints...
...)?x ?a n??? i=1 Notes: • x...
...on 0, . i=1 ? ? ?...
...?c = nc i=1 n n ?cai...
...?cai = c?ai i=1 i=1 n n(n+1)...
...= c?ai i=1 i=1 n n(n+1) ?i...
...n(n+1) ?i = i=1 2 n 2...
...n(n+1)(2n+1) ?i = i=1 6 n 2...
...= ? ? i=1 ? 2 ?...
...= ?ai +?bi i=1 i=1 i=1 n...
...?ai +?bi i=1 i=1 i=1 n n...
...+?bi i=1 i=1 i=1 n n n...
...= ?ai ??bi i=1 i=1 i=1 Example:...
...?ai ??bi i=1 i=1 i=1 Example: Consider...
...??bi i=1 i=1 i=1 Example: Consider the...
...f(x)= x between x=0and x=1. Recall that...
...x between x=0and x=1. Recall that we...
...shown here: > 1/n*(sum((i/n)^2,i=1..n)); > limit(%,n=infinity); MATH1010:...
...> 1/n*(sum((i/n)^2,i=1..n)); > limit(%,n=infinity); MATH1010: Chapter 5...
N/A 177
Lecture Notes | Approved: 7 years ago | 186.41 kB | Comments: 0
Category: Calculus | Downloaded: 0
N/A 143
Equation Sheet | Approved: 7 years ago | 28.75 kB | Comments: 1
Category: Calculus | Downloaded: 0
...2 2 sec (x)dx=tanx+C csc (x)dx=?cotx+C ?...
...(x)dx=?cotx+C ? ? sec(x)tan(x)dx=secx+C csc(x)cot(x)dx=?cscx+C ? ?...
...i ? = i=1 i=1 2 n...
...? = i=1 i=1 2 n n...
...? ? ? i=1 6 i=1 ?...
...? i=1 6 i=1 ? 2 ?...
...?1 2 sinh x=ln(x+ x +1)) will...
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